2+3+4=1+8
5+6+7+8+9=8+27
10+11+12+13+14+15+16=27+64
..........
(n2+1)+(n2+2)+...+(n+1)2=n3+(n+1)3
5+6+7+8+9=8+27
10+11+12+13+14+15+16=27+64
..........
(n2+1)+(n2+2)+...+(n+1)2=n3+(n+1)3
Tham khảo: Roger B Nelsen, Sums of integers as sums of cubes, Mathematics Magazine. Washington: Feb 1998. Vol. 71, Iss. 1; p. 65
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